Sunday, 1 May 2016

Interview Questions -- SQL Scenarios -- Part-1

Interview Questions -- SQL Scenarios -- Part-1

Scenario-1:   How to Get/See/Display duplicate records from                   the given table
Sample Scripts :- 
-- How to go inside to the Database
USE tempdb
GO
-- How to Create New Table
CREATE TABLE EMP
(
       EMPID INT
      ,EMPNAME VARCHAR(50)
      ,SAL MONEY
)
-- INSERT Sample Data Into the Table.
INSERT INTO EMP
SELECT 1,'Santhosh',10000
UNION ALL
SELECT 2,'Kumari',8000
UNION ALL
SELECT 2,'Kumari',8000
UNION ALL
SELECT 3,'Kamesh',75000
UNION ALL
SELECT 3,'Kamesh',75000
UNION ALL
SELECT 3,'Kamesh',75000



SELECT * FROM EMP



Expected Output :-  

Scenario-2:   How to Delete Duplicate records from                            the given table

Expected Output :-  


Guys you can share your Query Through Comments.


7 comments:

  1. Q1.By Using CTE Table, Row_Number and Where condition To find Duplication records.
    Query:
    WITH EMP_CTE
    AS
    (
    Select EMPID,
    EMPNAME,
    SAL,
    ROW_NUMBER() over(Partition by EMPID Order by EMPID) As Rank_Empid
    from emp
    )
    SELECT*FROM EMP_CTE
    where Rank_Empid>1

    ReplyDelete
  2. Q2.To Delete Duplicate records use Distinct.
    Query:
    Select Distinct * from emp

    ReplyDelete
  3. Thanks Bala for providing the description and queries in this blog. Really useful for all... :)

    - Shashi, Bangalore

    ReplyDelete
  4. Thank You Guys for your time.

    ReplyDelete
  5. Q1)TO DISPLAY THE DUPLICATE RECORDS

    SELECT * FROM
    (
    SELECT *,
    ROW_NUMBER() OVER(PARTITION BY EMPID ORDER BY EMPID DESC)ROW_ID
    FROM EM
    )E1
    WHERE ROW_ID>1

    ReplyDelete
  6. Q2)DELETE DUPLICATE RECORDS

    FIRST CREATE IDENTITY COLUMN (ID) FRO DUPLICATE RECORDS IDENTIFICATION

    DELETE FROM EMP
    WHERE ID IN
    (
    SELECT ID FROM
    (
    SELECT *
    ,ROW_NUMBER() OVER(PARTITION BY EMPID,EMPNAME,SAL ORDER BY ID DESC)AS ROW_ID
    FROM EMP
    )EMP1
    WHERE ROW_ID>1
    )

    ReplyDelete
  7. ;with cte as

    (

    select empid,empname,DENSE_RANK() over(order by sal desc) as rn from emp1
    )

    delete from cte where rn>1

    ReplyDelete